A) \[sp\]
B) \[s{{p}^{2}}\]
C) \[s{{p}^{3}}\]
D) none of these
Correct Answer: C
Solution :
Key Idea: Hybridisation\[=\frac{1}{2}\] [No. of electron in valence shell of central atom + No. of monovalent atoms + Charge on anion - Charge on cation] For \[\text{Xe}{{\text{O}}_{\text{4}}}\] Hybridisation \[=\frac{1}{2}(8+0+0-0)\] \[=4\] \[\therefore \] \[s{{p}^{3}}\]hybridisation.You need to login to perform this action.
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