A) zero matrix
B) A
C) \[I\]
D) 2A
Correct Answer: A
Solution :
Key Idea: If A in involutory matrix, then \[{{A}^{2}}=I\]Since, A is involutory matrix. \[\therefore \] \[{{A}^{2}}=I\] ?(i) Now, \[(I-A)(I+A)\] \[={{I}^{2}}-{{A}^{2}}\] \[=I-I\] [from (i)] \[=0\]You need to login to perform this action.
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