A) \[{{\sin }^{-1}}{{\left( \frac{P}{2Q} \right)}^{1/2}}\]
B) \[2{{\sin }^{-1}}{{\left( \frac{P}{2Q} \right)}^{1/2}}\]
C) \[{{\cos }^{-1}}{{\left( \frac{P}{2Q} \right)}^{1/2}}\]
D) \[2{{\cos }^{-1}}{{\left( \frac{P}{2Q} \right)}^{1/2}}\]
Correct Answer: B
Solution :
Let \[\alpha \]be the angle between the force and their resultant R makes an angle \[\theta \]with the direction of P. Then Resolved part of R in the direction of P \[=OM=R\cos \theta =Q\] (given)You need to login to perform this action.
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