A) 7
B) \[>7\]
C) \[<7\]
D) None of these
Correct Answer: B
Solution :
Given,\[NaOH\,V=10\,mL,\,N=0.1\] \[{{H}_{2}}S{{O}_{4}}V=10\,mL\,N=0.05\] Milli equivalents of\[NaOH=10\times 0.1=1\] Milli equivalents of \[{{H}_{2}}S{{O}_{4}}=10\times 0.05=0.5\] \[\because \]\[0.05\] milli equivalents of \[{{\text{H}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}\]neutralizes \[0.05\]milli equivalents of \[NaOH\]. \[\therefore \] \[0.05\]milli equivalents of \[NaOH\] will remain in solution. \[\therefore \]Solution is basic. Basic solution has\[pH>7\]. \[\therefore \]pH of solution is more than 7.You need to login to perform this action.
You will be redirected in
3 sec