A) \[m\,th\]
B) \[(n-1)\,th\]
C) \[(m+1)th\]
D) \[(m+2)th\]
Correct Answer: C
Solution :
Since, \[n=2m,\]i.e., n is even, so the middle term in the expansion of\[{{(x+a)}^{n}}\]is\[\left( \frac{2m}{2}+1 \right)th\] \[\text{=}\,\text{(m}\,\text{+}\,\text{1)}\,\text{th}\,\,\text{term}\]You need to login to perform this action.
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