A) \[+\,6\]
B) \[~+\,4\]
C) \[~+\,2\]
D) \[+\,3\]
Correct Answer: A
Solution :
Idea: The sum of oxidation states off elements in a compound is always zero. Let oxidation state of S in\[{{H}_{2}}S{{O}_{4}}=x.\] \[\therefore \] \[(+\,1\times 2)+x+(-2\times 4)=0\] or \[x+2-8=0\] \[\therefore \] \[x=+\,\,6\]You need to login to perform this action.
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