A) \[\text{50}\sqrt{3}\,m\]
B) \[100\,m\]
C) \[100(\sqrt{3}-1)\,m\]
D) \[100(\sqrt{3}+1)\,m\]
Correct Answer: C
Solution :
In \[\Delta ABC,\] \[\tan {{45}^{o}}=\frac{BC}{AB}\] \[\Rightarrow \] \[BC=100\] In \[\Delta ABD,\] \[\tan {{60}^{o}}=\frac{BD}{AB}\] \[\Rightarrow \]\[\sqrt{3}=\frac{BC+CD}{100}\] \[\Rightarrow \]\[CD=100\sqrt{3}-100\] \[\Rightarrow \]\[CD=100(\sqrt{3}-1)m\]You need to login to perform this action.
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