A) \[\frac{1}{\sin x}\]
B) \[{{\cos }^{-1}}x\]
C) \[-1\]
D) \[\frac{1}{2}\]
Correct Answer: C
Solution :
\[y={{\sin }^{-1}}(\cos x)\] \[={{\sin }^{-1}}\left( \sin \left( \frac{\pi }{2}-x \right) \right)\] \[\Rightarrow \] \[y=\frac{\pi }{2}-x\] On differentiating both sides, w.r.t. \[x,\] we get \[\frac{dy}{dx}=-1\]You need to login to perform this action.
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