A) \[\text{27 }\!\!\times\!\!\text{ 1}{{\text{0}}^{\text{39}}}\text{N}\]
B) \[\text{36 }\!\!\times\!\!\text{ 1}{{\text{0}}^{21}}\text{N}\]
C) \[\text{18 }\!\!\times\!\!\text{ 1}{{\text{0}}^{25}}\text{N}\]
D) \[\text{6 }\!\!\times\!\!\text{ 1}{{\text{0}}^{19}}\text{N}\]
Correct Answer: B
Solution :
Key Idea: Earth is acted upon by a centripetal force directed towards the sun. On the basis of Keplers law, Newton drew the following conclusion that planet is acted upon by a centripetal force directed towards the sun. Force is given by \[F=\frac{m{{v}^{2}}}{r}\] where v is velocity and r is the radius. Also, \[v=r\omega \] \[\therefore \] \[F=mr{{\omega }^{2}}\] Putting the numerical values, we have \[F=(6\times {{10}^{24}})\times (1.5\times {{10}^{11}})\times {{(2\times {{10}^{-7}})}^{2}}\] \[=36\times {{10}^{21}}\,N\] Note: This force is attractive in nature.You need to login to perform this action.
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