A) 2
B) 4
C) 6
D) 3
Correct Answer: B
Solution :
\[{{\left( \frac{1+i}{1-i} \right)}^{n}}={{\left( \frac{1+i}{1-i}\times \frac{1+i}{1+i} \right)}^{n}}\] \[={{\left( \frac{1-1+2i}{{{1}^{2}}+{{1}^{2}}} \right)}^{n}}\] \[\Rightarrow \] \[1={{(i)}^{n}}\] \[\Rightarrow \]\[n\]is a multiple of 4. \[\therefore \]The minimum value of n is 4You need to login to perform this action.
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