A) 0
B) 5
C) 1/6
D) 6
Correct Answer: B
Solution :
Let \[\alpha \] be the root of the equation \[5{{x}^{2}}+13x+k=0,\] then the other root will be\[\frac{1}{\alpha }.\] \[\ \therefore \] \[\alpha .\frac{1}{\alpha }=\frac{k}{5}\] \[\Rightarrow \] \[k=5\]You need to login to perform this action.
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