A) \[(0,4)\]
B) \[(2,0)\]
C) \[(-1/2,0)\]
D) none of these
Correct Answer: C
Solution :
We have, \[y={{e}^{2x}}\] On differentiating both sides w.r.t. \[x,\]we get \[\frac{dy}{dx}=2{{e}^{2x}}\] \[{{\left( \frac{dy}{dx} \right)}_{(0,1)}}=2{{e}^{o}}=2\] Equation of tangent at the point (0,1) is \[(y-1)=2(x-0)\] \[y=2x+1\] This line meet the \[x-\]axis at \[y=0,x=\frac{-1}{2}\]You need to login to perform this action.
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