A) 10 m/s
B) 50 m/s
C) 250 m/s
D) 500m/s
Correct Answer: B
Solution :
Key Idea: Frictional force provides the necessary centripetal force to the motor cycle to avoid skidding. Frictional force = centripetal force i.e., \[\mu R=\frac{m{{v}^{2}}}{r}\] but\[R=\] normal reaction \[=\text{ }mg\] \[\therefore \] \[\mu mg=\frac{m{{v}^{2}}}{r}\] Hence, maximum speed \[{{v}_{\max }}=\sqrt{\mu rg}\] Given, \[\mu =0.5,\,\,r=500m,\,g=10\,m/{{s}^{2}}\] \[{{v}_{\max }}=\sqrt{0.5\times 500\times 10}\] \[=\sqrt{5\times 500}\] \[=50\,m/s\]You need to login to perform this action.
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