A) 75 m/s
B) 150 m/s
C) 200 m/s
D) 300 m/s
Correct Answer: C
Solution :
If n is the frequency of the note emitted and \[v\]the velocity of sound and \[l\] the length of air column, then \[n=\frac{v}{4l}\] \[\therefore \] \[250=\frac{v}{4l}\] \[\Rightarrow \] \[v=250\times 4\times 0.2=200\,m/s\]You need to login to perform this action.
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