A) \[-200\]cal
B) \[-300\]cal
C) \[+\,200\]cal
D) \[+\text{ }300\]cal
Correct Answer: A
Solution :
Key Idea: From first law of thermodynamic. \[\Delta \Epsilon =q+W\] Given \[q=+\,300\,cal\](\[\because \]heat is absorbed) \[W=-500\,\text{cal}\] (\[\because \]work is done on surroundings). \[\therefore \] \[\Delta \Epsilon =q+W\] \[=300+(-500)\] \[=-200\,cal.\]You need to login to perform this action.
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