A) \[0.0797\text{ }kcal~~\]
B) \[-0.0797\text{ }kcal\]
C) \[1.435\text{ }kcal\]
D) \[-1.435\text{ }kcal\]
Correct Answer: B
Solution :
Key Idea: Enthalpy change per gram water is calculated by dividing\[\Delta H\] by molecular mass of water. Given \[\Delta H=1.4354\,kcal\,mo{{l}^{-1}}\] \[=-\frac{1.4354}{18}=-0.0797\,kcal\,{{g}^{-1}}\]You need to login to perform this action.
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