A) meta-formaldehyde
B) para-formaldehyde
C) urotropine
D) none of the above
Correct Answer: C
Solution :
Key Idea: Formaldehyde reacts with \[\text{N}{{\text{H}}_{\text{3}}}\]to form urotropine which is used as medicine to cure urinary infections. \[\underset{\text{formaldehyde}}{\mathop{6HCHO}}\,\,+\underset{\text{ammonia}}{\mathop{4\,N{{H}_{3}}}}\,\xrightarrow{{}}\underset{\begin{smallmatrix} \,\,\,\,\,\,\,\,\,\text{hexamethylene} \\ \text{tetramine}\,\text{or}\,\text{urotropine} \end{smallmatrix}}{\mathop{{{(C{{H}_{2}})}_{6}}{{N}_{4}}}}\,\] \[\underset{\text{formaldehyde}}{\mathop{\underset{(h)}{\mathop{HCHO}}\,}}\,\xrightarrow{37\,K}\underset{\text{paraformaldehyde}}{\mathop{{{(C{{H}_{2}}O)}_{n}}{{N}_{4}}}}\,\] \[3HCHO\xrightarrow[\text{stand}]{\text{allowed}\,\text{to}}\] \[\therefore \] (c) is the correct answer.You need to login to perform this action.
You will be redirected in
3 sec