A) one becquerel
B) one curie
C) one millicurie
D) one Rutherford
Correct Answer: C
Solution :
Key Idea: One curie is the amount of radio active element which gives \[3.7\times {{10}^{10}}\] disintegration per second, \[\therefore \] 1 millicurie \[=3.7\text{ }\times \text{ }{{10}^{7}}\text{ }dps.\]You need to login to perform this action.
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