A) 0.5
B) 0.44
C) 0.6
D) none of these
Correct Answer: B
Solution :
Key Idea: The probability of either \[X\]or \[Y\]fails in the examination is \[P(X\cup Y)=P(X)+P(Y)-P(X\cap Y).\] Give that \[P(X)=0.3,P(Y)=0.2\] \[\therefore \]\[P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)\] Since, the failure of \[X\] does not depends on the failure of \[Y,\]so \[X\]and \[Y\]are independent events. \[\therefore \]\[P(X\cup Y)=P(X)+P(Y)-P(X)\cap P(Y)\] \[=0.3+0.2-0.3\times 0.2\] \[=0.5-0.06\] \[=0.44\]You need to login to perform this action.
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