A) 2
B) 3
C) \[n\]
D) \[2n\]
Correct Answer: A
Solution :
Let\[f(x)={{x}^{2n}}-1\] Replacing \[x\]by\[-x,\] we get \[f(-x)={{(-x)}^{2n}}-1={{x}^{2n}}-1\] \[f(-x)=f(x)\] \[\therefore \]It is symmetrical about the y-axis. It is clear from the figure that curve intersect the real axis (i.e., \[x-\]axis) in two points, therefore the maximum number of possible real roots is 2. Note: The total number of real roots in \[nth\] roots of unity are 2 if \[n\]is even and 1, if \[n\]is odd.You need to login to perform this action.
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