A) AP
B) GP only when \[x>0\]
C) GP if \[x<0\]
D) GP
Correct Answer: D
Solution :
Since, a, b, c are in AP and let d be the common difference of AP. \[\therefore \] \[b=a+d,c=a+2d\] \[\therefore \] \[{{2}^{bx+1}}={{2}^{(a+d)x+1}}={{2}^{ax+1}}{{.2}^{dx}}\] and \[{{2}^{cx+1}}={{2}^{(a+2d)x+1}}\] \[={{2}^{ax+1}}{{({{2}^{dx}})}^{2}}\] \[\therefore \] These terms are in GP for all values of \[x.\]You need to login to perform this action.
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