A) ellipse
B) parabola
C) hyperbola
D) circle
Correct Answer: A
Solution :
We have \[\frac{x}{3}=(\cos t+\sin t),\frac{y}{4}=(\cos t-\sin t)\] On squaring and adding, we get \[\frac{{{x}^{2}}}{9}+\frac{{{y}^{2}}}{16}=2({{\cos }^{2}}t+{{\sin }^{2}}t)\] \[\Rightarrow \] \[\frac{{{x}^{2}}}{9}+\frac{{{y}^{2}}}{16}=2\] \[\Rightarrow \] \[\frac{{{x}^{2}}}{18}+\frac{{{y}^{2}}}{32}=1\] Which represents the equation of an ellipse.You need to login to perform this action.
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