A) extreme position
B) half of extreme position
C) equilibrium position
D) between extreme and equilibrium position
Correct Answer: C
Solution :
In case of SHM, when motion is considered from the equilibrium position, velocity at an instant t is given by \[v=\omega \sqrt{{{A}^{2}}-{{y}^{2}}}\] At the mean or equilibrium position i.e., when \[y=0\] \[v={{v}_{\max }}=\omega A\] At the extreme positions, i.e., when \[y=\pm A\] \[v={{v}_{\min }}=0\] Hence, velocity is maximum at equilibrium position.
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