A) \[x-y+5=0\]
B) \[x+y-5=0\]
C) \[~x-y-5=0\]
D) \[~x+y+5=0\]
Correct Answer: A
Solution :
The intercept form of equation of equal magnitude but opposite sign is \[\frac{x}{a}+\frac{y}{(-a)}=1\] \[\Rightarrow \] \[x-y=a\] Since, it is passing through \[(-3,2)\] \[\Rightarrow \] \[-3-2=a\]\[\Rightarrow \]\[a=-5\] \[\therefore \] \[x-y=-5\] \[\Rightarrow \] \[x-y+5=0\] Alternate Solution: Since the required line intercept the coordinate axes in equal magnitude and opposite sign, then the intercepted line make an angle \[{{45}^{o}}\]to the \[x-\]axis. \[\therefore \]Equation of straight line is \[\Rightarrow \] \[y-2=\tan {{45}^{o}}(x+3)\] \[\Rightarrow \] \[y-2=x+3\] \[\Rightarrow \] \[x-y+5=0\]You need to login to perform this action.
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