A) \[x{{y}_{1}}+{{x}_{1}}y=0\]
B) \[x{{x}_{1}}-y{{y}_{1}}=0\]
C) \[x{{x}_{1}}+y{{y}_{1}}=0\]
D) \[xy-{{x}_{1}}y=0\]
Correct Answer: C
Solution :
As we know that tangent on point \[({{x}_{1}},{{y}_{1}})\]of the circle \[{{x}^{2}}+{{y}^{2}}={{r}^{2}}\]is \[xx{{ & }_{1}}+y{{y}_{1}}={{r}^{2}}\] ?(i) The required line is parallel to the tangent line i.e., \[x{{x}_{1}}+y{{y}_{1}}=k\] Since, it is passing through origin \[\Rightarrow \] \[k=0\] \[\therefore \]\[x{{x}_{1}}+y{{y}_{1}}=0\]You need to login to perform this action.
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