A) odd
B) even
C) neither even nor odd
D) one-one
Correct Answer: B
Solution :
Let \[g(x)=\frac{1}{2}[f(x)+f(-x)]\] \[\Rightarrow \] \[g(-x)=\frac{1}{2}[f(-x)+f(x)]\] \[\Rightarrow \] \[g(x)=g(-x)\] \[\therefore \] It is an even function. Note: In any function, if we replace \[x\]by the function does not change the sign, that is an \[-x,\]even function.You need to login to perform this action.
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