A) \[1\mu F\]
B) \[2\mu F\]
C) \[4\mu F\]
D) \[8\mu F\]
Correct Answer: A
Solution :
The two capacitors each of value \[1.5\,\mu F\]are in parallel, so their equivalent capacitance. \[{{C}_{1}}=1.5+1.5=3\,\mu F\] Now, three capacitors each of value \[3\,\mu F\]are in series. Hence, their equivalent capacitance is given by \[\frac{1}{C}=\frac{1}{3}+\frac{1}{3}+\frac{1}{3}\] or \[\frac{1}{C}=\frac{3}{3}\] or \[C=1\,\mu F\]You need to login to perform this action.
You will be redirected in
3 sec