A) zero
B) 6 cm
C) 10 cm
D) 15 cm
Correct Answer: B
Solution :
When a thin glass plate of thickness t is placed over one of the slits, then lateral displacement is given by \[x=\frac{(\mu -1)tD}{d}\] Given, \[\mu =1.5\,,t=0.06\,mm=6\times {{10}^{-5}}m\] \[D=2m,\] \[d=1\,mm=1\times {{10}^{-3}}\,m\] Putting the values in the above relation, we get \[x=\frac{(1.5-1)\times 6\times {{10}^{-5}}\times 2}{1\times {{10}^{-3}}}\] \[=0.5\times 12\times {{10}^{-2}}\] \[=0.06\,m\] \[=6\,cm\] Note: Lateral displacement is independent of \[\lambda \]i.e., if white light is used. Then shift of red colour fringe = shift of violet colour fringeYou need to login to perform this action.
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