A) 1.4 L
B) 2.8 L
C) 11.2 L
D) 22.4 L
Correct Answer: A
Solution :
Key Idea: Molecular mass in gram = 22.4 L at STP. Given mass of \[{{O}_{2}}=2g\]at \[27{{\,}^{o}}C\]and 760 mm Hg \[32\text{ }g\text{ }of\text{ }{{\text{O}}_{2}}=22.4\text{ }L\]at STP \[\therefore \] \[2g\]of \[{{O}_{2}}\]\[=\frac{22.4}{32}\times 2=1.4\,L\]You need to login to perform this action.
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