A) \[{{I}_{2}}\]
B) \[I_{3}^{-}\]
C) \[{{I}^{-}}\]
D) None of these
Correct Answer: C
Solution :
Key Idea: Electron donors are Lewis base. In the reaction \[{{I}_{2}}+{{I}^{-}}\xrightarrow{{}}{{I}^{3-}},{{I}^{-}}\]donates a pair of electron and \[{{I}_{2}}\]accepts it to form \[{{I}^{3-}}\] \[\therefore \] \[{{I}^{-}}\]is Lewis base.You need to login to perform this action.
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