A) \[\frac{1}{2}Fx\]
B) \[\frac{1}{2}Yx\]
C) \[\frac{1}{2}F{{x}^{2}}\]
D) none of these
Correct Answer: A
Solution :
The potential energy of the stretched wire is \[U=\frac{1}{2}\times \text{stress}\,\text{ }\!\!\times\!\!\text{ }\,\text{strain}\] \[=\frac{1}{2}\times F\times x=\frac{1}{2}Fx\]You need to login to perform this action.
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