A) 0.56 cm
B) 1.35 cm
C) 0.41 cm
D) 2.32 cm
Correct Answer: C
Solution :
Key Idea: At the same level in the two limbs of a U-tube, pressure is same. On pouring water on left side, mercury rises \[x\,cm\](say) from its previous level in the right limb of U-tube creating a difference of levels of mercury by \[2x\text{ }cm.\]Equating pressures at A and B, we get \[{{P}_{A}}={{P}_{B}}\] \[\therefore \] \[11.2\times {{10}^{-2}}\times {{\rho }_{\text{water}}}\times g=2x\times {{\rho }_{\text{mercury}}}\times g\] \[\Rightarrow \]\[11.2\times {{10}^{-2}}\times 1000\,kg/{{m}^{3}}\] \[=2x\times 13600\times \,kg/{{m}^{3}}\] \[\Rightarrow \] \[x=\frac{11.2\times {{10}^{-2}}\times 1000\,m}{2\times 13600}\] \[=0.41\,cm\]You need to login to perform this action.
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