A) \[7{}^\circ C\]
B) \[65{}^\circ C\]
C) \[63{}^\circ C\]
D) \[35{}^\circ C\]
Correct Answer: D
Solution :
The relation between Celsius scale and Fahrenheit scale is as derived below: 100 parts of Celsius scale = 180 parts of Fahrenheit scale \[\therefore \]1 part of Celsius scale \[=\frac{9}{5}\] parts of Fahrenheit scale Hence, \[{{T}_{F}}=32+\frac{9}{5}{{T}_{C}}\] or \[{{T}_{C}}=\frac{5}{9}({{T}_{F}}-32)\] Given, \[{{T}_{F}}={{95}^{o}}F\] \[\therefore \] \[{{T}_{C}}=\frac{5}{9}(95-32)\] \[=35{{\,}^{o}}C\]You need to login to perform this action.
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