A) \[{{n}_{A}}={{n}_{B}}\]
B) \[{{n}_{A}}>{{n}_{B}}\]
C) \[{{n}_{A}}<{{n}_{B}}\]
D) either (b) or (c) depending on the ratio of their diameters
Correct Answer: C
Solution :
In the fundamental mode of vibration \[\frac{\lambda }{4}=(l+0.3d)\] where 0.3 d is the necessary end correction. Frequency of vibration,\[n=\frac{v}{\lambda }=\frac{v}{4(l+0.3d)}\] As \[l\]is same for both pipes, wider pipe (A) will resonate at a lower frequency i.e., \[{{n}_{A}}<{{n}_{B}}.\]You need to login to perform this action.
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