A) \[\frac{\pi }{4}\]
B) \[\frac{\pi }{3}\]
C) \[\frac{\pi }{2}\]
D) none of these
Correct Answer: C
Solution :
Given equation of curves are \[y={{x}^{2}}\]and \[6y=7-{{x}^{3}}.\] \[\ \therefore \] \[{{m}_{1}}={{\left( \frac{dy}{dx} \right)}_{(1,1)}}=2(1)=2\] and \[{{m}_{2}}={{\left( \frac{dy}{dx} \right)}_{(1,1)}}=-\frac{1}{2}\] Now, \[{{m}_{1}}{{m}_{2}}=2\times \left( -\frac{1}{2} \right)=-1\] \[\therefore \] The angle of intersection of the curves is \[\frac{\pi }{2}.\]You need to login to perform this action.
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