A) \[-312\,J\]
B) \[+\,123J\]
C) \[-213\,J\]
D) \[+\,231\,J\]
Correct Answer: C
Solution :
\[W=-\int_{{{V}_{1}}}^{{{V}_{2}}}{PdV}=-P({{V}_{2}}-{{V}_{1}})\] \[W=-1(20-10)=-10\,d{{m}^{3}}\text{atm}\] \[=-10\,d{{m}^{3}}\times \frac{8.314\,J{{K}^{-1}}\,mo{{l}^{-1}}}{0.0821\,d{{m}^{3}}\,{{K}^{-1}}\,mo{{l}^{-1}}}\] \[=-1013\,J\] From 1st law of thermodynamic \[\Delta U=q+W\] \[=800\,J+(-1013\,J)=-213\,J\]You need to login to perform this action.
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