A) Zero
B) 0.6 A
C) 0.9 A
D) 1.5 A
Correct Answer: D
Solution :
Key Idea: In the steady state there is no current in the capacitor branch. In the given circuit the resistors of \[2\,\Omega \] and \[3\,\Omega \] are connected in parallel hence, equivalent resistance is \[\frac{1}{R}=\frac{1}{2}+\frac{1}{3}=\frac{5}{6}\] \[\therefore \] \[R=\frac{6}{5}\Omega \] Also in steady state, the circuit is shown as. Resistors of \[\frac{6}{5}\Omega \] and \[2.8\,\Omega \] are connected in series Hence, \[R\,=\frac{6}{5}\Omega +2.8\,\Omega \] \[=1.2\Omega +2.8\Omega \] \[=4.0\,\Omega \] From Ohms law, Current \[i=\frac{V}{R}=\frac{6}{4.0}=1.5A\]You need to login to perform this action.
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