A) \[\frac{2}{7}\]
B) \[\frac{2}{9}\]
C) \[\frac{1}{9}\]
D) \[\frac{4}{9}\]
Correct Answer: B
Solution :
Total number of way of sitting \[=9!\] and number of favourable ways of sitting \[=2\times 8!\] \[\therefore \] Required probability \[=\frac{2\times 8!}{9!}=\frac{2}{9}.\]You need to login to perform this action.
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