A) 1, 2, 3
B) 1, 1, 1
C) \[\frac{1}{3},\frac{1}{3},\frac{1}{3}\]
D) \[\frac{1}{3},\frac{-1}{3},\frac{1}{3}\]
Correct Answer: A
Solution :
The given equation is \[6x-2=3y-1=2z-2\] \[\Rightarrow \]\[\frac{x-\frac{1}{3}}{1}=y\frac{y-\frac{1}{3}}{2}=\frac{z-1}{3}\] This shows that DRs of given equation are (1, 2, 3).You need to login to perform this action.
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