A) \[\frac{4Q}{2\pi \,{{\varepsilon }_{0}}{{R}^{2}}}\]
B) \[\frac{3Q}{4\pi \,{{\varepsilon }_{0}}{{R}^{2}}}\]
C) \[\frac{3Q}{2\pi \,{{\varepsilon }_{0}}{{R}^{2}}}\]
D) \[\frac{Q}{2\pi \,{{\varepsilon }_{0}}R}\]
Correct Answer: B
Solution :
The electric field inside a spherical charge is everywhere zero, that is \[E=0\] But point P is outside the inner sphere, hence for a point very close to the surface the intensity of electric field is given by \[E=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{q}{{{R}^{2}}}\] Given, \[q=+\,3Q\] Therefore, \[E=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{3Q}{{{R}^{2}}}\]You need to login to perform this action.
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