A) 0.1
B) 0.2
C) 0.3
D) 0.4
Correct Answer: C
Solution :
Since, \[P(B)=\frac{2}{7}\]and \[P(A\cap {{B}^{c}})=0.8\] \[P({{B}^{c}})=1-\frac{2}{7}=\frac{5}{7}\] We know that, \[P(A\cup {{B}^{c}})=P(A)+P({{B}^{c}})-P(A).P({{B}^{c}})\] \[\Rightarrow \]\[0.8=P(A)+\frac{5}{7}-\frac{5}{7}p(A)\] \[\Rightarrow \]\[0.8=\frac{5}{7}+\frac{2}{7}p(A)\] \[\Rightarrow \]\[5.6-5=2P(A)\] \[\Rightarrow \]\[p(A)=0.3\]You need to login to perform this action.
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