A) \[2x-3y+1=0\]
B) \[~6x-9y+11=0\]
C) \[~2x-3y+5=0\]
D) \[3x-2y+1=0\]
Correct Answer: A
Solution :
Given, equation of lines are \[x-3y+2=0\] ?(i) and \[2x+5y-7=0\] ?(ii) On solving Eqs. (i) and (ii), we get \[x=1,y=1\] \[\therefore \] The coordinates of a point of intersection of given lines are (1, 1). The equation of line perpendicular to \[3x+2y+5=0\] Its also passes through (1, 1). \[\therefore \] \[2-3+\lambda =0\] \[\Rightarrow \] \[\lambda =1\] \[\therefore \]Required equation of line is \[2x-3y+1=0\]You need to login to perform this action.
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