BCECE Engineering BCECE Engineering Solved Paper-2008

  • question_answer
    If the direction cosines of two lines are such that \[l+m+n=0,{{l}^{2}}+{{m}^{2}}-{{n}^{2}}=,0\]then the angle between them is

    A)  \[\pi \]                  

    B)         \[\pi /3\]              

    C)        \[\pi /4\]                               

    D)         \[\pi /6\]

    Correct Answer: B

    Solution :

    If \[l,m,n\]are direction cosines of two lines are such that \[l+m+n=0\]                                       ...(i) and        \[{{l}^{2}}+{{m}^{2}}-{{n}^{2}}=0\]           ?(ii)       \[\Rightarrow \]\[{{l}^{2}}+{{m}^{2}}-{{(-1-m)}^{2}}=0\] \[\Rightarrow \]\[2\,lm=0\] \[\Rightarrow \]\[l=0\]or \[m=0\] If             \[l=0,\]then\[n=-m\]  \[\Rightarrow \]              \[l:m:n=0:1:-1\] and if \[m=0,\]then\[n=-1\] \[\Rightarrow \]\[l:m:n=1:0:-1\] \[\therefore \]  \[\cos \theta =\frac{0+0+1}{\sqrt{0+1+1}\sqrt{0+1+1}}=\frac{1}{2}\] \[\Rightarrow \]               \[\theta =\frac{\pi }{3}\]


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