BCECE Engineering BCECE Engineering Solved Paper-2008

  • question_answer
    Forces of magnitudes 5N, 10N, 15N and 20 N   act on a particle in the direction of North, South, East and West respectively. The magnitude of their resultant is

    A)  \[15\sqrt{2}N\]   

    B)         \[10\,N\]              

    C)         \[25\sqrt{2}\,N\]                

    D)  \[5\sqrt{2}\,N\]

    Correct Answer: D

    Solution :

    Required resultant \[=\sqrt{{{(15-20)}^{2}}+{{(5-10)}^{2}}}\] \[=\sqrt{25+25}\] \[=5\sqrt{2}N\]


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