BCECE Engineering BCECE Engineering Solved Paper-2008

  • question_answer
    The sum of two vectors \[\vec{A}\] and \[\vec{B}\] is at right angles to their difference. Then

    A) \[A=B\]               

    B) \[A=2B\]

    C) \[B=2A\]             

    D) \[\vec{A}\] and \[\vec{B}\] have the same direction

    Correct Answer: A

    Solution :

    Key Idea If two vectors are at right angles, then their dot product will be zero. The sum of vectors\[\vec{A}\] and \[\vec{B}\] \[\vec{R}{{  }_{1}}=\vec{A}+\vec{B}\] The difference of vectors \[\vec{A}\]and \[\vec{B}\] \[\vec{R}{{  }_{2}}=\vec{A}-\vec{B}\] Since, \[{{\vec{R}}_{1}}\]and \[{{\vec{R}}_{2}}\]are at right angles, their dot product will be zero, ie, \[{{\vec{R}}_{1}}.{{\vec{R}}_{2}}=(\vec{A}+\vec{B}).(\vec{A}-\vec{B})\]                                or \[0=\vec{A}.\vec{A}-\vec{A}.\vec{B}+\vec{B}+\vec{B}.\vec{A}-\vec{B}.\vec{B}\]                 or \[0={{A}^{2}}-{{B}^{2}}\]         (as \[\vec{A}.\vec{B}=\vec{B}.\vec{A}\])                 \[\therefore \]  \[{{A}^{2}}={{B}^{2}}\]or  \[A=B\]


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