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BCECE Engineering BCECE Engineering Solved Paper-2008

  • question_answer
    Three blocks of masses 2 kg, 3 kg and 5 kg are connected to each other with light string and are then placed on a frictionless surface as shown in the figure. The system is pulled by a force \[F=10N,\]then tension \[{{T}_{1}}=\]        

    A)  1 N                       

    B)         5 N

    C)  8 N                       

    D)         10 N

    Correct Answer: C

    Solution :

    Total mass of the system, \[M={{m}_{1}}+{{m}_{2}}+{{m}_{3}}\] \[=2+3+5\] \[=10\,kg\] Force     \[F=10\,N\] Hence, acceleration, \[a=\frac{F}{M}=1\,m{{s}^{-2}}\] Now, tension \[{{T}_{1}}\]can be calculated as, \[{{T}_{1}}=({{m}_{2}}+{{m}_{3}})a=8\times 1=8N\]


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