A) time
B) mass
C) length
D) force
Correct Answer: A
Solution :
Dimensions of \[E=[M{{L}^{2}}{{T}^{-2}}]\] Dimensions of \[G=[{{M}^{-1}}{{L}^{3}}{{T}^{-2}}]\] Dimensions of \[I=[ML{{T}^{-1}}]\] and dimensions of \[M=[M]\] So, dimensions of\[\frac{G{{\operatorname{IM}}^{2}}}{{{E}^{2}}}\] \[=\frac{[G][I][{{M}^{2}}]}{[{{E}^{2}}]}\] Substituting the dimensions for each physical quantity, we get Dimensions of\[\frac{GI{{M}^{2}}}{{{E}^{2}}}\] \[=\frac{[{{M}^{-1}}{{L}^{3}}{{T}^{-2}}][ML{{T}^{-1}}][{{M}^{2}}]}{{{[M{{L}^{2}}{{T}^{-2}}]}^{2}}}\] \[=[T]\] = Dimensions of timeYou need to login to perform this action.
You will be redirected in
3 sec