BCECE Engineering BCECE Engineering Solved Paper-2009

  • question_answer
    \[\int_{{}}^{{}}{\frac{({{\sec }^{2}}x-7)}{{{\sin }^{7}}x}}dx\]is equal to

    A) \[\frac{\tan x}{{{\sin }^{7}}x}+C\]                            

    B)  \[\frac{\cos x}{{{\sin }^{7}}x}+C\]

    C)  \[\frac{\sin x}{{{\cos }^{7}}x}+C\]

    D)  \[\frac{\sin x}{{{\tan }^{7}}x}+C\]

    Correct Answer: A

    Solution :

    Let \[I=\int_{{}}^{{}}{\frac{{{\sec }^{2}}x-7}{{{\sin }^{7}}x}}dx\] \[=\int_{{}}^{{}}{\frac{{{\sin }^{7}}x{{\sec }^{2}}x-7{{\sin }^{7}}x}{{{({{\sin }^{7}}x)}^{2}}}}dx\] \[=\int_{{}}^{{}}{\frac{d}{dx}\left( \frac{\tan x}{{{\sin }^{7}}x} \right)}dx\] \[=\frac{\tan x}{{{\sin }^{7}}x}+C\]


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