A) 6
B) 8
C) 10
D) 12
Correct Answer: C
Solution :
Given curve is \[16{{x}^{2}}+25{{y}^{2}}=400\] \[\Rightarrow \]\[\frac{{{x}^{2}}}{25}+\frac{{{y}^{2}}}{16}=1\] Here \[a=5,b=4\] \[{{F}_{1}}\]and \[{{F}_{2}}\]are forcus. \[\therefore \]\[P{{F}_{1}}+P{{F}_{2}}=2a=10\]You need to login to perform this action.
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