A) \[\sqrt{14}\]
B) \[\sqrt{18}\]
C) \[\sqrt{29}\]
D) 4
Correct Answer: B
Solution :
Position vector of median \[\overrightarrow{AD}=\frac{\overrightarrow{AB}+\overrightarrow{AC}}{2}\] \[=\frac{(-3+5)\hat{i}(0-2)\hat{j}+(4+4)\hat{k}}{2}\] \[=\hat{i}-\hat{j}+4\hat{k}\] \[\therefore \]\[|\overrightarrow{AD}|=\sqrt{{{1}^{2}}+{{(-1)}^{2}}+{{(4)}^{2}}}=\sqrt{18}\]You need to login to perform this action.
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